#### Question :

There are 104 students in class X and 96 students in class IX in a school. In a house examination, the students are to be evenly seated in parallel rows such that no two adjacent rows are of the same class. (a) Find the maximum number of parallel rows of each class for the seating arrange¬ment. (b) Also, find the number of students of class IX and also of class X in a row.Submitted on 3/3/2024 | Answered by Vandana Rana#### Answer :

104 = 2³× 1396 = 2⁵× 3

HCF = 8

(a) Number of rows of students of class X = 104/8

= 13

Number maximum of rows class IX = 96/8

= 12

Total number of rows = 13 + 12 = 25

(b) No. of students of class IX in a row = 8

No. of students of class X in a row = 8