The melting points of three solids X Y and Z are 298K 310K and 400K respectively Arrange these in increasing order of their inter-particle force of attraction

Answers

Question :

The melting points of three solids X, Y and Z are 298K, 310K and 400K, respectively. Arrange these in increasing order of their inter-particle force of attraction.
Submitted on 21/8/2024 | Answered by Vandana Rana

Answer :

The molecules having high melting points will have high intermolecular forces and hence the order of intermolecular forces is

X
<
Y
<
Z