Question :

A train starting from rest attains a velocity of 72 km/h in 5 minutes. Assuming that the acceleration is uniform, find the acceleration and the distance travelled by train for attaining this velocity.
Submitted on 17/2/2024 | Answered by Vandana Rana

Answer :

The initial velocity of the train, u = 0
Final velocity of train, v = 72 km/h
=72×5/18 m/s = 20 m/s
Time taken, t = 5 minutes = 300 s

Let a, s be acceleration and distance covered by the train.

v = u + at
20=0+a×300
a = 20/ 300
a = 1/15 m/s²
s=ut+1/2at²
s =(0)t+12(1/15)(300)²
s = 3000 m
s = 3km

Hence, the distance travelled by train is 3 km.